Integrand size = 35, antiderivative size = 225 \[ \int \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {2 a^2 (143 A+112 C) \tan (c+d x)}{165 d \sqrt {a+a \sec (c+d x)}}+\frac {2 a^2 (33 A+28 C) \sec ^3(c+d x) \tan (c+d x)}{231 d \sqrt {a+a \sec (c+d x)}}-\frac {4 a (143 A+112 C) \sqrt {a+a \sec (c+d x)} \tan (c+d x)}{1155 d}+\frac {2 a C \sec ^3(c+d x) \sqrt {a+a \sec (c+d x)} \tan (c+d x)}{33 d}+\frac {2 (143 A+112 C) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{385 d}+\frac {2 C \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{11 d} \]
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Time = 0.87 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.171, Rules used = {4174, 4103, 4101, 3885, 4086, 3877} \[ \int \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {2 a^2 (33 A+28 C) \tan (c+d x) \sec ^3(c+d x)}{231 d \sqrt {a \sec (c+d x)+a}}+\frac {2 a^2 (143 A+112 C) \tan (c+d x)}{165 d \sqrt {a \sec (c+d x)+a}}+\frac {2 (143 A+112 C) \tan (c+d x) (a \sec (c+d x)+a)^{3/2}}{385 d}-\frac {4 a (143 A+112 C) \tan (c+d x) \sqrt {a \sec (c+d x)+a}}{1155 d}+\frac {2 C \tan (c+d x) \sec ^3(c+d x) (a \sec (c+d x)+a)^{3/2}}{11 d}+\frac {2 a C \tan (c+d x) \sec ^3(c+d x) \sqrt {a \sec (c+d x)+a}}{33 d} \]
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Rule 3877
Rule 3885
Rule 4086
Rule 4101
Rule 4103
Rule 4174
Rubi steps \begin{align*} \text {integral}& = \frac {2 C \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{11 d}+\frac {2 \int \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \left (\frac {1}{2} a (11 A+6 C)+\frac {3}{2} a C \sec (c+d x)\right ) \, dx}{11 a} \\ & = \frac {2 a C \sec ^3(c+d x) \sqrt {a+a \sec (c+d x)} \tan (c+d x)}{33 d}+\frac {2 C \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{11 d}+\frac {4 \int \sec ^3(c+d x) \sqrt {a+a \sec (c+d x)} \left (\frac {9}{4} a^2 (11 A+8 C)+\frac {3}{4} a^2 (33 A+28 C) \sec (c+d x)\right ) \, dx}{99 a} \\ & = \frac {2 a^2 (33 A+28 C) \sec ^3(c+d x) \tan (c+d x)}{231 d \sqrt {a+a \sec (c+d x)}}+\frac {2 a C \sec ^3(c+d x) \sqrt {a+a \sec (c+d x)} \tan (c+d x)}{33 d}+\frac {2 C \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{11 d}+\frac {1}{77} (a (143 A+112 C)) \int \sec ^3(c+d x) \sqrt {a+a \sec (c+d x)} \, dx \\ & = \frac {2 a^2 (33 A+28 C) \sec ^3(c+d x) \tan (c+d x)}{231 d \sqrt {a+a \sec (c+d x)}}+\frac {2 a C \sec ^3(c+d x) \sqrt {a+a \sec (c+d x)} \tan (c+d x)}{33 d}+\frac {2 (143 A+112 C) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{385 d}+\frac {2 C \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{11 d}+\frac {1}{385} (2 (143 A+112 C)) \int \sec (c+d x) \left (\frac {3 a}{2}-a \sec (c+d x)\right ) \sqrt {a+a \sec (c+d x)} \, dx \\ & = \frac {2 a^2 (33 A+28 C) \sec ^3(c+d x) \tan (c+d x)}{231 d \sqrt {a+a \sec (c+d x)}}-\frac {4 a (143 A+112 C) \sqrt {a+a \sec (c+d x)} \tan (c+d x)}{1155 d}+\frac {2 a C \sec ^3(c+d x) \sqrt {a+a \sec (c+d x)} \tan (c+d x)}{33 d}+\frac {2 (143 A+112 C) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{385 d}+\frac {2 C \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{11 d}+\frac {1}{165} (a (143 A+112 C)) \int \sec (c+d x) \sqrt {a+a \sec (c+d x)} \, dx \\ & = \frac {2 a^2 (143 A+112 C) \tan (c+d x)}{165 d \sqrt {a+a \sec (c+d x)}}+\frac {2 a^2 (33 A+28 C) \sec ^3(c+d x) \tan (c+d x)}{231 d \sqrt {a+a \sec (c+d x)}}-\frac {4 a (143 A+112 C) \sqrt {a+a \sec (c+d x)} \tan (c+d x)}{1155 d}+\frac {2 a C \sec ^3(c+d x) \sqrt {a+a \sec (c+d x)} \tan (c+d x)}{33 d}+\frac {2 (143 A+112 C) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{385 d}+\frac {2 C \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{11 d} \\ \end{align*}
Time = 1.24 (sec) , antiderivative size = 142, normalized size of antiderivative = 0.63 \[ \int \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {a^2 (1188 A+1652 C+(4147 A+4228 C) \cos (c+d x)+2 (737 A+728 C) \cos (2 (c+d x))+1859 A \cos (3 (c+d x))+1456 C \cos (3 (c+d x))+286 A \cos (4 (c+d x))+224 C \cos (4 (c+d x))+286 A \cos (5 (c+d x))+224 C \cos (5 (c+d x))) \sec ^5(c+d x) \tan (c+d x)}{2310 d \sqrt {a (1+\sec (c+d x))}} \]
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Time = 1.01 (sec) , antiderivative size = 144, normalized size of antiderivative = 0.64
method | result | size |
default | \(\frac {2 a \left (1144 A \cos \left (d x +c \right )^{5}+896 C \cos \left (d x +c \right )^{5}+572 A \cos \left (d x +c \right )^{4}+448 C \cos \left (d x +c \right )^{4}+429 A \cos \left (d x +c \right )^{3}+336 C \cos \left (d x +c \right )^{3}+165 A \cos \left (d x +c \right )^{2}+280 C \cos \left (d x +c \right )^{2}+245 C \cos \left (d x +c \right )+105 C \right ) \sqrt {a \left (1+\sec \left (d x +c \right )\right )}\, \tan \left (d x +c \right ) \sec \left (d x +c \right )^{4}}{1155 d \left (\cos \left (d x +c \right )+1\right )}\) | \(144\) |
parts | \(\frac {2 A a \left (104 \cos \left (d x +c \right )^{3}+52 \cos \left (d x +c \right )^{2}+39 \cos \left (d x +c \right )+15\right ) \sqrt {a \left (1+\sec \left (d x +c \right )\right )}\, \tan \left (d x +c \right ) \sec \left (d x +c \right )^{2}}{105 d \left (\cos \left (d x +c \right )+1\right )}+\frac {2 C a \left (128 \cos \left (d x +c \right )^{5}+64 \cos \left (d x +c \right )^{4}+48 \cos \left (d x +c \right )^{3}+40 \cos \left (d x +c \right )^{2}+35 \cos \left (d x +c \right )+15\right ) \sqrt {a \left (1+\sec \left (d x +c \right )\right )}\, \tan \left (d x +c \right ) \sec \left (d x +c \right )^{4}}{165 d \left (\cos \left (d x +c \right )+1\right )}\) | \(168\) |
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Time = 0.27 (sec) , antiderivative size = 139, normalized size of antiderivative = 0.62 \[ \int \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {2 \, {\left (8 \, {\left (143 \, A + 112 \, C\right )} a \cos \left (d x + c\right )^{5} + 4 \, {\left (143 \, A + 112 \, C\right )} a \cos \left (d x + c\right )^{4} + 3 \, {\left (143 \, A + 112 \, C\right )} a \cos \left (d x + c\right )^{3} + 5 \, {\left (33 \, A + 56 \, C\right )} a \cos \left (d x + c\right )^{2} + 245 \, C a \cos \left (d x + c\right ) + 105 \, C a\right )} \sqrt {\frac {a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )}{1155 \, {\left (d \cos \left (d x + c\right )^{6} + d \cos \left (d x + c\right )^{5}\right )}} \]
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\[ \int \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\int \left (a \left (\sec {\left (c + d x \right )} + 1\right )\right )^{\frac {3}{2}} \left (A + C \sec ^{2}{\left (c + d x \right )}\right ) \sec ^{3}{\left (c + d x \right )}\, dx \]
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Timed out. \[ \int \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\text {Timed out} \]
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\[ \int \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\int { {\left (C \sec \left (d x + c\right )^{2} + A\right )} {\left (a \sec \left (d x + c\right ) + a\right )}^{\frac {3}{2}} \sec \left (d x + c\right )^{3} \,d x } \]
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Time = 41.94 (sec) , antiderivative size = 751, normalized size of antiderivative = 3.34 \[ \int \sec ^3(c+d x) (a+a \sec (c+d x))^{3/2} \left (A+C \sec ^2(c+d x)\right ) \, dx=\text {Too large to display} \]
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